10 passengers board a matatu with exactly 10 seats. Everyone has a ticket with an assigned seat number. However, the first passenger has lost their ticket and takes a random seat. Every subsequent passenger attempts to choose their own seat, but takes a random seat if their’s is taken. Suppose you are the very last passenger to board the matatu. What is the probability that you will get your assigned seat?
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the more practical answer involves combining increasing probabilities that each passenger will sit on the last passenger’s space from 1/10, 1/9… to 1/2. You will get the probability that someone will take the last passenger’s seat. Subtract this from 1 to get the probability that the last passenger will get their seat. Its very low. Closer to 0 than it is to 1. Do the math.
Zero.
That thing requires a complex formula… a concept which needs to be learned.
You need someone who has specialized in that area or a university student who has just done the unit Probability and Statistics II.
This is entry level stats. Kama ulisoma book ya KLB Mathematics form three unafaa kujua
Gari ni watu 14 but mko watu kumi there is four extra seats utashindwa aje kuchagua nugu wewe
Nilisoma na kuchambua hiyo book vizuri sana na pia nikafanya probability university (Poisson distribution, Binomial distribution etc) though it is not my area of specialization
Hii ni pre-covid ama vipi?
You need to establish the number of combinations and permutations
1/ (9!) Factorial of 9.
Probability should be 1/10 - Yours was only 1 out of the 10 seats…
Sometimes thinking like a lay man helps you in Nairobi not to get robbed. Don’t overcomplicate things. The answer to most problems is right there on your nose.
To
Probability should be 1/10 if say there are ten seats and you have one seat among them. Then what is the probability of someone choosing your seat. Hapo ndio unasema sasa 1/10
The probability of that a seat is selected at the kth draw is equal to the probability it is selected in the first draw,so I think it’s still 1/10
Cannot be factoral ,1/10c1 ie combination
No that stuff keeps on reducing
Actually
The probability that you will get your own seat =
Probability that the first guy gets their seat & the second gets their seat and the third gets their seat and so on and also you get your seat =
= 1/10 * 1/9 * 1/8 * 1/7 * 1/6 * 1/5 * 1/4 * 1/3 * 1/2 * 1
=
Suppose the last person does select his/her own seat,then, then the probability it’s not selected by the 1st person would be 9/10,the second would be 8/9,third 7/8 and so on.Now take the product to obtain the probability that the seat is not selected by all the other passengers
P=9/108/97/86/75/64/53/42/31/2
P=1/10
Yeah i agree with you